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Combination of Resistors question from NEET 2024

Q19NEET 2024Medium

Combination of Resistors

A wire of length ' $l$ ' and resistance $100\ \Omega$ is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:

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Answer: (b)

Each part has $\dfrac{100}{10} = 10\ \Omega$ .
5 parts in series: $50\ \Omega$ . 5 parts in parallel: $\dfrac{10}{5} = 2\ \Omega$ .
Total in series: $50 + 2 = 52\ \Omega$
So the answer is (b) $52\ \Omega$ .

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