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NEET 2020 (Phase 1) · Young's Modulus & Elongation

Young's Modulus & Elongation question from NEET 2020 (Phase 1)

Q23NEET 2020 · PHASE 1Easy

Young's Modulus & Elongation

A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changed to L1 when mass M is suspended from its free end. The expression for Young's modulus is:

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Answer: (c)

Stress $= \frac{Mg}{A}$ , strain $= \frac{L_1 - L}{L}$
$Y = \frac{\text{stress}}{\text{strain}} = \frac{MgL}{A(L_1 - L)}$
So the answer is (c).

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