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MHT CET 2025 (5 May, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2025 (5 May, Shift 2)

Q25MHT CET 2025 · 5 MAY · SHIFT 2Medium

Current Loop as a Magnetic Dipole

A wire of length ' LL ' carries a current ' II '. If the wire is turned into a square coil of single turn, the maximum magnitude of the torque in a given magnetic field (B⃗)(\vec{B}) is

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Answer: (d)

  1. Square of side L4\frac{L}{4}: A=L216A = \frac{L^2}{16}.
  2. τmax=IAB=IBL216\tau_{max} = IAB = \frac{IBL^2}{16}
  3. So the answer is (d).
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