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MHT CET 2021 (21 Sep, Shift 1) · Motional EMF

Motional EMF question from MHT CET 2021 (21 Sep, Shift 1)

Q37MHT CET 2021 · 21 SEP · SHIFT 1Medium

Motional EMF

A wire of length 'LL'; having resistance 'RR' falls from a height 'ℓ\ell' in earth's horizontal magnetic field 'BB'. The current through the wire is ( g=g = acceleration due to gravity)

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Answer: (a)

  1. Speed after falling height ℓ\ell: v=2gℓv = \sqrt{2g\ell}.
  2. ε=BLv=BL2gℓ\varepsilon = BLv = BL\sqrt{2g\ell}
  3. I=εR=BL2gℓRI = \frac{\varepsilon}{R} = \frac{BL\sqrt{2g\ell}}{R}. So the answer is (a).
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