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JEE Main 2023 (12 Apr, Shift 1) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2023 (12 Apr, Shift 1)

Q21JEE Main 2023 · 12 APR · SHIFT 1Medium

Ohm's Law, Resistivity & Temperature

A wire of resistance 160 Ω160\ \Omega is melted and drawn in a wire of one-fourth of its length. The new resistance of the wire will be

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Answer: (d)

  1. Volume constant: l→l/4l \to l/4 means A→4AA \to 4A, so R∝l2R \propto l^2.
  2. R′=160×(1/4)2=10 ΩR' = 160\times(1/4)^2 = 10\ \Omega. The answer is (d).
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