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JEE Main 2024 (5 Apr, Shift 2) · Combination of Resistors

Combination of Resistors question from JEE Main 2024 (5 Apr, Shift 2)

Q20JEE Main 2024 · 5 APR · SHIFT 2Medium

Combination of Resistors

A wire of resistance 20 Ω20\ \Omega is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is _________ Ω\Omega.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. Each part is 2010=2 Ω\dfrac{20}{10} = 2\ \Omega.
  2. Each pair in parallel: 22=1 Ω\dfrac{2}{2} = 1\ \Omega; there are 5 pairs.
  3. 5 pairs in series: 5×1=5 Ω5 \times 1 = 5\ \Omega
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