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JEE Main 2022 (28 Jul, Shift 1) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2022 (28 Jul, Shift 1)

Q25JEE Main 2022 · 28 JUL · SHIFT 1Easy

Ohm's Law, Resistivity & Temperature

A wire of resistance R1 is drawn out so that its length is increased by twice of its original length. The ratio of new resistance to original resistance is:

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Answer: (a)

  1. Length increased by twice its original length: l′=l+2l=3ll' = l + 2l = 3l.
  2. At constant volume R∝l2R \propto l^2, so R′/R=32=9R'/R = 3^2 = 9.
  3. So the answer is (a) 9:19:1.
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