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MHT CET 2024 (2 May, Shift 1) · Beats

Beats question from MHT CET 2024 (2 May, Shift 1)

Q35MHT CET 2024 · 2 MAY · SHIFT 1Medium

Beats

A wire under tension 225 N produces 6 beats per second when it is tuned with a fork. When the tension changes to 256 N, it is again tuned with the same tuning fork, the number of beats remain unchanged. The frequency of tuning fork will be

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Answer: (b)

  1. f∝Tf \propto \sqrt{T}: 225=15\sqrt{225} = 15, 256=16\sqrt{256} = 16.
  2. Same beats, so at 225 N the wire gives n−6n - 6 and at 256 N it gives n+6n + 6.
  3. n−6n+6=1516⇒16n−96=15n+90\dfrac{n - 6}{n + 6} = \dfrac{15}{16} \Rightarrow 16n - 96 = 15n + 90
  4. n=186 Hzn = 186\text{ Hz}. So the answer is (b) 186 Hz.
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