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JEE Main 2024 (5 Apr, Shift 1) · Apparent Weight & Lift

Apparent Weight & Lift question from JEE Main 2024 (5 Apr, Shift 1)

Q6JEE Main 2024 · 5 APR · SHIFT 1Easy

Apparent Weight & Lift

A wooden block of mass 5 kg5\text{ kg} rests on a soft horizontal floor. When an iron cylinder of mass 25 kg25\text{ kg} is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of 0.1 ms−20.1\text{ ms}^{-2}. The action force of the system on the floor is equal to:

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Answer: (b)

  1. System mass =5+25=30= 5 + 25 = 30 kg, accelerating down with a=0.1 m s−2a = 0.1\text{ m s}^{-2}.
  2. N=m(g−a)=30×(9.8−0.1)=30×9.7N = m(g - a) = 30 \times (9.8 - 0.1) = 30 \times 9.7
  3. N=291N = 291 N; by Newton's third law the force on the floor is 291 N.
  4. So the answer is (b) 291 N.
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