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MHT CET 2024 (4 May, Shift 1) · Special Purpose Diodes

Special Purpose Diodes question from MHT CET 2024 (4 May, Shift 1)

Q32MHT CET 2024 · 4 MAY · SHIFT 1Medium

Special Purpose Diodes

A zener diode, having breakdown voltage 15 V is used in a voltage regulator circuit as shown. The current through the zener diode is

Figure

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Answer: (b)

  1. Output held at 1515 V, so drop across 250 Ω250\ \Omega is 20−15=520 - 15 = 5 V.
  2. I=5250=20I = \frac{5}{250} = 20 mA
  3. IL=151000=15I_L = \frac{15}{1000} = 15 mA
  4. IZ=20−15=5I_Z = 20 - 15 = 5 mA, so the answer is (b).
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