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NEET 2011 (AIPMT, Mains) · Special Purpose Diodes

Special Purpose Diodes question from NEET 2011 (AIPMT, Mains)

Q93NEET 2011 · AIPMT · MAINSMedium

Special Purpose Diodes

A Zener diode, having breakdown voltage equal to 15 V, is used in a voltage regulator circuit shown in figure. The current through the diode is

Figure

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Answer: (a)

  1. Output held at 1515 V, so drop across 250 Ω250\ \Omega is 20−15=520 - 15 = 5 V.
  2. I=5250=20I = \frac{5}{250} = 20 mA
  3. IL=151 kΩ=15I_L = \frac{15}{1\text{ k}\Omega} = 15 mA
  4. IZ=20−15=5I_Z = 20 - 15 = 5 mA, so the answer is (a).
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