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JEE Main 2024 (30 Jan, Shift 1) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2024 (30 Jan, Shift 1)

Q34JEE Main 2024 · 30 JAN · SHIFT 1Medium

Special Purpose Diodes

A Zener diode of breakdown voltage 10 V10\text{ V} is used as a voltage regulator as shown in the figure. The current through the Zener diode is:

Figure

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Answer: (b)

  1. Without the Zener the load would get 20×500700≈14.320 \times \frac{500}{700} \approx 14.3 V >10> 10 V, so the Zener conducts and holds 1010 V.
  2. I=20−10200=50I = \frac{20 - 10}{200} = 50 mA
  3. IL=10500=20I_L = \frac{10}{500} = 20 mA
  4. IZ=50−20=30I_Z = 50 - 20 = 30 mA, so the answer is (b).
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