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JEE Main 2021 (27 Aug, Shift 2) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2021 (27 Aug, Shift 2)

Q66JEE Main 2021 · 27 AUG · SHIFT 2Medium

Special Purpose Diodes

A zener diode of power rating 2W is to be used as a voltage regulator. If the zener diode has a breakdown of 10 V and it has to regulate voltage fluctuated between 6 V and 14 V, the value of Rs for safe operation should be ___________ Ω\Omega.

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Numerical answer type. Work it out, then open the answer.

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Answer: 20

  1. Maximum safe Zener current: I=PVZ=210=0.2I = \frac{P}{V_Z} = \frac{2}{10} = 0.2 A
  2. Worst case is the highest input 1414 V: drop across Rs=14−10=4R_s = 14 - 10 = 4 V.
  3. Rs=40.2=20 ΩR_s = \frac{4}{0.2} = 20\ \Omega
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