Physics Circle home Student Login

Home›Chapters›Electromagnetic Induction PYQs›Combination of Inductors, LR & LC Circuits›Question 16

NEET 2025 · Combination of Inductors, LR & LC Circuits

Combination of Inductors, LR & LC Circuits question from NEET 2025

Q16NEET 2025Medium

Combination of Inductors, LR & LC Circuits

ABAB is a part of an electrical circuit (see figure). The potential difference " VA−VBV_A - V_B ", at the instant when current i=2 Ai = 2\text{ A} and is increasing at a rate of 1 amp/1\text{ amp/} second is:

Figure

Show answer and solution

Answer: (b)

  1. Go from AA to BB along ii: VA−Ldidt−5−iR=VBV_A - L\frac{di}{dt} - 5 - iR = V_B (battery crossed from ++ to −-).
  2. VA−VB=1×1+5+2×2=10 VV_A - V_B = 1\times1 + 5 + 2\times2 = 10\text{ V}
  3. So the answer is (b) 10 volt.
Report a mistake

More questions on Combination of Inductors, LR & LC Circuits