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MHT CET 2026 (11 Apr, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2026 (11 Apr, Shift 2)

Q19MHT CET 2026 · 11 APR · SHIFT 2Medium

Matter Waves: de Broglie Wavelength

According to de-Broglie hypothesis, the ratio of the wave-length of a photon and that of an electron having same energy 'E' is (m = mass of electron, c = velocity of light)

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Answer: (c)

  1. Photon: λph=hcE\lambda_{ph} = \dfrac{hc}{E}. Electron: λe=h2mE\lambda_e = \dfrac{h}{\sqrt{2mE}}.
  2. λphλe=c2mEE=c2mE\dfrac{\lambda_{ph}}{\lambda_e} = \dfrac{c\sqrt{2mE}}{E} = c\sqrt{\dfrac{2m}{E}}
  3. So the answer is (c).
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