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MHT CET 2026 (20 Apr, Shift 2) · Law of Radioactive Decay

Law of Radioactive Decay question from MHT CET 2026 (20 Apr, Shift 2)

Q3MHT CET 2026 · 20 APR · SHIFT 2Easy

Law of Radioactive Decay

Activity of a radioactive sample decreases to $\left(\frac{1}{4}\right)^{th}$ of its original value in 4 days. Then in 16 days its activity will become $x$ times the original value. The value of $x$ is

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Answer: (c)

Activity falls by factor $\frac{1}{4}$ every 4 days.
16 days = 4 intervals: $x = \left(\frac{1}{4}\right)^4 = \frac{1}{256}$ .
So the answer is (c) $\frac{1}{256}$ .

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