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MHT CET 2024 (15 May, Shift 1) · AC Generator & Transformer

AC Generator & Transformer question from MHT CET 2024 (15 May, Shift 1)

Q23MHT CET 2024 · 15 MAY · SHIFT 1Medium

AC Generator & Transformer

Alternating current of peak value $\left(\frac{2}{\pi}\right)$ A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1 H. The peak e.m.f. induced in secondary coil (Frequency of a.c. $= 50\text{ Hz}$ )

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Answer: (d)

Peak induced emf $e_0 = M\omega I_0$ .
$\omega = 2\pi \times 50 = 100\pi\text{ rad/s}$
$e_0 = 1 \times 100\pi \times \dfrac{2}{\pi} = 200\text{ V}$
So the answer is (d) 200 V.

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