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MHT CET 2026 (11 Apr, Shift 2) · Mutual Inductance

Mutual Inductance question from MHT CET 2026 (11 Apr, Shift 2)

Q7MHT CET 2026 · 11 APR · SHIFT 2Easy

Mutual Inductance

Alternating current of peak value (2π)\left(\frac{2}{\pi}\right) A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 11 H. The peak em.f. induced in secondary coil is (Frequency of a. c. is 5050 Hz)

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Answer: (d)

  1. emax⁡=MI0ωe_{\max} = M I_0 \omega with ω=2πf=100π\omega = 2\pi f = 100\pi rad/s.
  2. emax⁡=1×2π×100π=200e_{\max} = 1 \times \dfrac{2}{\pi} \times 100\pi = 200 V
  3. So the answer is (d) 200200 V.
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