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MHT CET 2026 (16 Apr, Shift 2) · AC Generator & Transformer

AC Generator & Transformer question from MHT CET 2026 (16 Apr, Shift 2)

Q7MHT CET 2026 · 16 APR · SHIFT 2Medium

AC Generator & Transformer

Alternating current of peak value $\left(\frac{2}{\pi}\right)$ A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1H. The peak value of induced e.m.f. in the secondary coil is

(Frequency of a.c. = 50 Hz)

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Answer: (c)

$e = M\dfrac{dI}{dt}$ ; for $I = I_0\sin\omega t$ , peak $e_0 = M\omega I_0$ .
$\omega = 2\pi \times 50 = 100\pi\text{ rad/s}$
$e_0 = 1 \times 100\pi \times \dfrac{2}{\pi} = 200\text{ V}$
So the answer is (c) 200 V.

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