An a. c. voltage is applied to pure inductor. The current in the inductor (a) leads the voltage by (π/4)c (b) leads the voltage by (π/2)c (c) lags behind the voltage by (π/2)c (d) lags behind the voltage by (3π/4)c

Answer: (c). For a pure inductor, E = LdI/dt; with E = E₀sin ω t, I = -(E₀)/(ω L)cos ω t = (E₀)/(ω L)sin (ω t - π/2). Current lags the voltage by π/2 rad. So the answer is (c).

An a. c. voltage is applied to pure inductor. The current in the… | MHT CET 2025 (25 Apr, Shift 1)

Q16MHT CET 2025 · 25 APR · SHIFT 1Easy

Pure R, L and C Circuits

An a. c. voltage is applied to pure inductor. The current in the inductor

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Answer: (c)

For a pure inductor, $E = L\frac{dI}{dt}$ ; with $E = E_0\sin\omega t$ , $I = -\frac{E_0}{\omega L}\cos\omega t = \frac{E_0}{\omega L}\sin\left(\omega t - \frac{\pi}{2}\right)$ .
Current lags the voltage by $\frac{\pi}{2}$ rad.
So the answer is (c).

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Pure R, L and C Circuits question from MHT CET 2025 (25 Apr, Shift 1)

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