Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›Resonance, Bandwidth & Q Factor›Question 7

NEET 2026 · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from NEET 2026

Q7NEET 2026Easy

Resonance, Bandwidth & Q Factor

An ac circuit contains a resistance of 1 kΩ1\text{ k}\Omega, a capacitor of 0.1 μF0.1\ \mu\text{F} and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately:

Show answer and solution

Answer: (d)

  1. Resonance: f0=12πLCf_0 = \dfrac{1}{2\pi\sqrt{LC}}
  2. LC=(10−3)(10−7)=10−10⇒LC=10−5 sLC = (10^{-3})(10^{-7}) = 10^{-10} \Rightarrow \sqrt{LC} = 10^{-5}\text{ s}
  3. f0=1052π≈1.59×104 Hzf_0 = \dfrac{10^{5}}{2\pi} \approx 1.59\times10^{4}\text{ Hz}
  4. So the answer is (d) 15.9 kHz.
Report a mistake

More questions on Resonance, Bandwidth & Q Factor