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JEE Main 2021 (27 Aug, Shift 2) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from JEE Main 2021 (27 Aug, Shift 2)

Q57JEE Main 2021 · 27 AUG · SHIFT 2Medium

Power, Power Factor & Wattless Current

An ac circuit has an inductor and a resistor of resistance R in series, such that XL = 3R. Now, a capacitor is added in series such that XC = 2R. The ratio of new power factor with the old power factor of the circuit is 5:x\sqrt{5}:x. The value of x is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. Old: Z=R2+9R2=10RZ=\sqrt{R^2+9R^2}=\sqrt{10}R, cos⁡ϕ1=1/10\cos\phi_1 = 1/\sqrt{10}.
  2. New: X=3R−2R=RX = 3R-2R = R, Z=2RZ=\sqrt{2}R, cos⁡ϕ2=1/2\cos\phi_2 = 1/\sqrt{2}.
  3. cos⁡ϕ2cos⁡ϕ1=102=5:1\frac{\cos\phi_2}{\cos\phi_1} = \frac{\sqrt{10}}{\sqrt{2}} = \sqrt{5}:1
  4. So x=1x = 1.
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