An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3 Ω, the phase difference between the applied voltage and the current in the circuit is (a) π/6 (b) π/4 (c) π/2 (d) zero

Answer: (b). tan φ = XL/R = 3/3 = 1 φ = 45° = π/4 So the answer is (b) π/4.

An ac voltage is applied to a resistance R and an inductor L in… | NEET 2011 (AIPMT, Prelims)

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RL and RC Series Circuits

An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3 $\Omega$ , the phase difference between the applied voltage and the current in the circuit is

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Answer: (b)

$\tan\phi = \frac{X_L}{R} = \frac{3}{3} = 1$
$\phi = 45^\circ = \frac{\pi}{4}$
So the answer is (b) $\pi/4$ .

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