An aeroplane having a wing span of 30 m flies due north with the speed of 170 m/s. Magnetic field B = 3.6 × 10⁻⁵ T. The potential difference between the tips of the wings will be (a) 136.4 mV (b) 183.6 mV (c) 272.8 mV (d) 367.2 mV

Answer: (b). Horizontal wings cut the vertical component of the field: ε = Blv. ε = 3.6×10⁻⁵ × 30 × 170 = 0.1836 V = 183.6 mV. So the answer is (b).

An aeroplane having a wing span of 30 m flies due north with the… | MHT CET 2026 (20 Apr, Shift 2)

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An aeroplane having a wing span of 30 m flies due north with the speed of 170 m/s. Magnetic field $B = 3.6 \times 10^{-5}$ T. The potential difference between the tips of the wings will be

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Answer: (b)

Horizontal wings cut the vertical component of the field: $\varepsilon = Blv$ .
$\varepsilon = 3.6\times10^{-5} \times 30 \times 170 = 0.1836$ V
$= 183.6$ mV. So the answer is (b).

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