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MHT CET 2026 (13 May, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (13 May, Shift 1)

Q13MHT CET 2026 · 13 MAY · SHIFT 1Medium

Self-Inductance & Energy

An air cored coil has a self inductance of 0.10.1 H. A soft iron core of relative permeability 10001000 is th\text{th}

introduced inside cored coil and number of turns reduced to (110)\left(\frac{1}{10}\right). The value of self inductance now becomes

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Answer: (c)

  1. For a coil L=μrμ0N2AlL = \dfrac{\mu_r \mu_0 N^2 A}{l}, so L∝μrN2L \propto \mu_r N^2.
  2. L′=0.1×1000×(110)2=0.1×10L' = 0.1 \times 1000 \times \left(\dfrac{1}{10}\right)^2 = 0.1 \times 10
  3. So the answer is (c) 11 H.
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