An air craft of wing span 40 m flies horizontally in earth's magnetic field 5 × 10⁻⁵ T at a speed of 500 m/s. The e.m.f. generated between the tips of the wings of the air craft is (a) 0.5 V (b) 1 V (c) 1.2 V (d) 1.5 V

Answer: (b). Emf between wing tips ε = Blv (with B the field component cutting the wings). ε = 5×10⁻⁵ × 40 × 500 = 1 V So the answer is (b) 1 V.

An air craft of wing span 40 m flies horizontally in earth's magnetic… | MHT CET 2023 (12 May, Shift 2)

Q26MHT CET 2023 · 12 MAY · SHIFT 2Easy

Motional EMF

An air craft of wing span $40\text{ m}$ flies horizontally in earth's magnetic field $5 \times 10^{-5}\text{ T}$ at a speed of $500\text{ m/s}$ . The e.m.f. generated between the tips of the wings of the air craft is

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Answer: (b)

Emf between wing tips $\varepsilon = Blv$ (with $B$ the field component cutting the wings).
$\varepsilon = 5\times10^{-5} \times 40 \times 500 = 1$ V
So the answer is (b) 1 V.

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