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NEET 2010 (AIPMT, Prelims) · Atomic Models & Alpha-Particle Scattering

Atomic Models & Alpha-Particle Scattering question from NEET 2010 (AIPMT, Prelims)

Q13NEET 2010 · AIPMT · PRELIMSEasy

Atomic Models & Alpha-Particle Scattering

An alpha nucleus of energy $\frac{1}{2}$ mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

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Answer: (c)

$\frac{1}{2}mv^2 = \dfrac{k(2e)(Ze)}{r_0} \Rightarrow r_0 = \dfrac{4kZe^2}{mv^2}$ .
So $r_0 \propto Ze$ , $r_0 \propto \dfrac{1}{v^2}$ and $r_0 \propto \dfrac{1}{m}$ .
So the answer is (c) $\frac{1}{m}$ .

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