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JEE Main 2024 (4 Apr, Shift 1) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from JEE Main 2024 (4 Apr, Shift 1)

Q18JEE Main 2024 · 4 APR · SHIFT 1Easy

AC Basics: Peak, RMS & Average Values

An alternating current at any instant is given by $i = [6 + \sqrt{56} \sin(100\pi t + \pi/3)]$ A. The rms value of the current is ______ A.

Numerical answer type. Work it out, then open the answer.

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Answer: 8

For dc + sinusoid: $I_{rms}^2 = I_{dc}^2 + \frac{I_0^2}{2}$ .
$I_{rms}^2 = 6^2 + \frac{56}{2} = 36 + 28 = 64$
$I_{rms} = 8$ A

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