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JEE Main 2025 (4 Apr, Shift 1) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from JEE Main 2025 (4 Apr, Shift 1)

Q11JEE Main 2025 · 4 APR · SHIFT 1Easy

AC Basics: Peak, RMS & Average Values

An alternating current is represented by the equation, $i = 100\sqrt{2} \sin(100\pi t)$ ampere. The RMS value of current and the frequency of the given alternating current are

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Answer: (d)

$I_{rms} = \frac{I_0}{\sqrt{2}} = \frac{100\sqrt{2}}{\sqrt{2}} = 100$ A
$\omega = 100\pi = 2\pi f \Rightarrow f = 50$ Hz
So the answer is (d) $100$ A, $50$ Hz.

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