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MHT CET 2025 (21 Apr, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2025 (21 Apr, Shift 2)

Q17MHT CET 2025 · 21 APR · SHIFT 2Medium

Series LCR Circuit

An alternating e.m.f. having voltage $V = V_0 \sin\omega t$ is applied to a series L-C-R circuit. Given: $|X_L - X_C| = R$ . The r.m.s. value of potential difference across capacitor will be

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Answer: (c)

$Z = \sqrt{R^2 + R^2} = \sqrt{2}R$
$I_{rms} = \frac{V_0/\sqrt{2}}{\sqrt{2}R} = \frac{V_0}{2R}$
$V_C = I_{rms} X_C = \frac{V_0}{2R} \cdot \frac{1}{\omega C} = \frac{V_0}{2R\omega C}$
So the answer is (c).

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