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MHT CET 2025 (22 Apr, Shift 2) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from MHT CET 2025 (22 Apr, Shift 2)

Q14MHT CET 2025 · 22 APR · SHIFT 2Medium

AC Basics: Peak, RMS & Average Values

An alternating e.m.f. is given by $e = e_0 \sin \omega t$ . In how much time the e.m.f. will have half its maximum value, if e starts from zero?

$(T =$ Time Period, $\sin 30^\circ = \frac{1}{2})$

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Answer: (c)

$e = \frac{e_0}{2} \Rightarrow \sin\omega t = \frac{1}{2} \Rightarrow \omega t = \frac{\pi}{6}$
$\frac{2\pi}{T}t = \frac{\pi}{6} \Rightarrow t = \frac{T}{12}$
So the answer is (c) $\frac{T}{12}$ .

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