Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›AC Basics: Peak, RMS & Average Values›Question 7

MHT CET 2026 (13 Apr, Shift 1) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from MHT CET 2026 (13 Apr, Shift 1)

Q7MHT CET 2026 · 13 APR · SHIFT 1Medium

AC Basics: Peak, RMS & Average Values

An alternating e.m.f. is given by e=e0sin⁡ωte = e_0 \sin \omega t. In what time the e.m.f. will have half its maximum value, if 'e' starts from zero? (sin⁡30∘=0.5\sin 30^\circ = 0.5)

Show answer and solution

Answer: (c)

  1. e=e02⇒sin⁡ωt=12⇒ωt=π6e = \frac{e_0}{2} \Rightarrow \sin\omega t = \frac{1}{2} \Rightarrow \omega t = \frac{\pi}{6}
  2. 2πTt=π6⇒t=T12\frac{2\pi}{T}t = \frac{\pi}{6} \Rightarrow t = \frac{T}{12}
  3. So the answer is (c) T12\frac{T}{12}.
Report a mistake

More questions on AC Basics: Peak, RMS & Average Values