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MHT CET 2026 (14 May, Shift 2) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from MHT CET 2026 (14 May, Shift 2)

Q3MHT CET 2026 · 14 MAY · SHIFT 2Easy

AC Basics: Peak, RMS & Average Values

An alternating voltage is E=100sin⁡(ωt+π6)E = 100 \sin\left(\omega t + \frac{\pi}{6}\right) V. The voltage will be maximum for the first time when t is

(sin⁡π2=1)\left(\sin \frac{\pi}{2} = 1\right) (T = Periodic time)

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Answer: (c)

  1. Maximum when ωt+π6=π2\omega t + \frac{\pi}{6} = \frac{\pi}{2}, so ωt=π3\omega t = \frac{\pi}{3}.
  2. 2πTt=π3⇒t=T6\frac{2\pi}{T}t = \frac{\pi}{3} \Rightarrow t = \frac{T}{6}
  3. So the answer is (c) T6\frac{T}{6}.
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