An alternating voltage is given by E = 100 sin (ω t + π/6) V. The voltage will be maximum for the first time when is [ T = periodic time) (a) T/12 (b) T/2 (c) T/6 (d) T/3

Answer: (c). Maximum when ω t + π/6 = π/2, so ω t = π/3. 2π/Tt = π/3 ⇒ t = T/6 So the answer is (c) T/6.

An alternating voltage is given by E = 100 sin (ω t + π/6) V. The… | MHT CET 2019 (2 May, Shift 2)

Q38MHT CET 2019 · 2 MAY · SHIFT 2Easy

AC Basics: Peak, RMS & Average Values

An alternating voltage is given by $E = 100 \sin\left(\omega t + \frac{\pi}{6}\right)\text{ V}$ . The voltage will be maximum for the first time when is [ $T =$ periodic time)

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Answer: (c)

Maximum when $\omega t + \frac{\pi}{6} = \frac{\pi}{2}$ , so $\omega t = \frac{\pi}{3}$ .
$\frac{2\pi}{T}t = \frac{\pi}{3} \Rightarrow t = \frac{T}{6}$
So the answer is (c) $\frac{T}{6}$ .

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AC Basics: Peak, RMS & Average Values question from MHT CET 2019 (2 May, Shift 2)

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