An alternating voltage v = 200√(2) sin (100t) is connected to a 1 μ F capacitor through an a. c. ammeter. The reading of the ammeter shall be (a) 10 mA (b) 20 mA (c) 40 mA (d) 80 mA

Answer: (b). Ammeter reads rms current: Irms = Vrms ω C. Vrms = 200 V, ω = 100 rad/s, C = 10⁻⁶ F. Irms = 200 × 100 × 10⁻⁶ = 0.02 A = 20 mA So the answer is (b) 20 mA.

An alternating voltage v = 200√(2) sin (100t) is connected to a 1 μ F… | MHT CET 2024 (3 May, Shift 1)

Q27MHT CET 2024 · 3 MAY · SHIFT 1Easy

Pure R, L and C Circuits

An alternating voltage $v = 200\sqrt{2} \sin(100t)$ is connected to a $1\ \mu F$ capacitor through an a. c. ammeter. The reading of the ammeter shall be

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Answer: (b)

Ammeter reads rms current: $I_{rms} = V_{rms}\,\omega C$ .
$V_{rms} = 200$ V, $\omega = 100$ rad/s, $C = 10^{-6}$ F.
$I_{rms} = 200 \times 100 \times 10^{-6} = 0.02$ A $= 20$ mA
So the answer is (b) 20 mA.

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