An alternating voltage V = 200√(2) sin (100t) volt is connected to 1 μ F capacitor through ammeter (AC). The reading of ammeter is (in mA) (a) 5 (b) 10 (c) 15 (d) 20

Answer: (d). ω = 100 rad/s, XC = (1)/(ω C) = 1100 × 10⁻⁶ = 10⁴ Ω Vrms = (200√(2))/(√(2)) = 200 V Irms = (200)/(10⁴) = 0.02 A = 20 mA So the answer is (d) 20.

An alternating voltage V = 200√(2) sin (100t) volt is connected to 1… | MHT CET 2026 (15 May, Shift 2)

Q7MHT CET 2026 · 15 MAY · SHIFT 2Easy

Pure R, L and C Circuits

An alternating voltage $V = 200\sqrt{2} \sin(100t)$ volt is connected to $1\ \mu F$ capacitor through ammeter (AC). The reading of ammeter is (in mA)

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Answer: (d)

$\omega = 100$ rad/s, $X_C = \frac{1}{\omega C} = \frac{1}{100 \times 10^{-6}} = 10^4\ \Omega$
$V_{rms} = \frac{200\sqrt{2}}{\sqrt{2}} = 200$ V
$I_{rms} = \frac{200}{10^4} = 0.02$ A $= 20$ mA
So the answer is (d) 20.

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