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MHT CET 2021 (21 Sep, Shift 1) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from MHT CET 2021 (21 Sep, Shift 1)

Q30MHT CET 2021 · 21 SEP · SHIFT 1Easy

AC Basics: Peak, RMS & Average Values

An alternating voltge is represented by V=80sin⁡(100πt)cos⁡(100πt)V = 80 \sin(100\pi t) \cos(100\pi t) volt. The peak voltage is

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Answer: (b)

  1. Use 2sin⁡θcos⁡θ=sin⁡2θ2\sin\theta\cos\theta = \sin 2\theta.
  2. V=40×2sin⁡(100πt)cos⁡(100πt)=40sin⁡(200πt)V = 40 \times 2\sin(100\pi t)\cos(100\pi t) = 40\sin(200\pi t)
  3. Peak voltage =40= 40 V
  4. So the answer is (b) 4040 V.
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