Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Kirchhoff's Laws & Measuring Instruments›Question 201

JEE Main 2003 (AIEEE) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2003 (AIEEE)

Q201JEE Main 2003 · AIEEEEasy

Kirchhoff's Laws & Measuring Instruments

An ammeter reads upto 11 ampere. Its internal resistance is 0.81 ohm0.81\text{ ohm}. To increase the range to 10 A10\text{ A} the value of the required shunt is

Show answer and solution

Answer: (d)

  1. Shunt for an ammeter: S=G IgI−IgS = \frac{G\,I_g}{I - I_g}, with Ig=1I_g = 1 A and G=0.81 ΩG = 0.81\ \Omega.
  2. S=0.81×110−1=0.819S = \frac{0.81 \times 1}{10 - 1} = \frac{0.81}{9}
  3. So the answer is (d) 0.09 Ω0.09\ \Omega.
Report a mistake

More questions on Kirchhoff's Laws & Measuring Instruments