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MHT CET 2025 (5 May, Shift 2) · Logic Gates

Logic Gates question from MHT CET 2025 (5 May, Shift 2)

Q35MHT CET 2025 · 5 MAY · SHIFT 2Easy

Logic Gates

An AND gate is followed by a NOT gate in series. With two inputs ' $A$ ' and ' $B$ ', the Boolean expression for the output ' Y ' will be

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Answer: (b)

AND output is $A \cdot B$ .
NOT inverts it: $Y = \overline{A \cdot B}$ (NAND).
So the answer is (b) $\overline{A \cdot B}$ .

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