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JEE Main 2005 (AIEEE) · Rolling Motion

Rolling Motion question from JEE Main 2005 (AIEEE)

Q85JEE Main 2005 · AIEEEDifficult

Rolling Motion

An annular ring with inner and outer radii $R_1$ and $R_2$ is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring, $\frac{F_1}{F_2}$ is

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Answer: (c)

Uniform $\omega$ means the centre moves with constant velocity; in that frame each particle moves in a circle.
Force on a particle $= m\omega^2 r$ , so $F \propto r$ for equal masses.
$\dfrac{F_1}{F_2} = \dfrac{R_1}{R_2}$ .
So the answer is (c).

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