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MHT CET 2026 (14 May, Shift 2) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from MHT CET 2026 (14 May, Shift 2)

Q17MHT CET 2026 · 14 MAY · SHIFT 2Medium

Power, Power Factor & Wattless Current

An arc lamp requires a direct current of 1010 A at 9090 V to function. If it is connected to 220220 V (rms), 5050 Hz a.c. supply, the series inductor needed for it to work is nearly

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Answer: (b)

  1. Lamp resistance R=90/10=9 ΩR = 90/10 = 9\ \Omega.
  2. Needed impedance Z=220/10=22 ΩZ = 220/10 = 22\ \Omega.
  3. XL=222−92=403≈20 ΩX_L = \sqrt{22^2-9^2} = \sqrt{403} \approx 20\ \Omega
  4. L=XL2πf=20100π=15πL = \frac{X_L}{2\pi f} = \frac{20}{100\pi} = \frac{1}{5\pi} H, so the answer is (b).
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