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MHT CET 2024 (16 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2024 (16 May, Shift 2)

Q34MHT CET 2024 · 16 MAY · SHIFT 2Easy

Biot-Savart Law & Circular Coils

An arc of a circle of radius ' $R$ ' subtends an angle $\frac{\pi}{2}$ at the centre. It carries a current $I$ . The magnetic field at the centre will be ( $\mu_0 =$ permeability of free space)

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Answer: (b)

Arc of angle $\theta$ : $B = \frac{\mu_0 I\theta}{4\pi R}$ .
$\theta = \frac{\pi}{2}$ : $B = \frac{\mu_0 I}{8R}$
So the answer is (b).

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