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MHT CET 2026 (13 May, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2026 (13 May, Shift 1)

Q5MHT CET 2026 · 13 MAY · SHIFT 1Easy

Biot-Savart Law & Circular Coils

An arc of a circle of radius R subtends an angle π/2\pi/2 at the centre. It carries a current I. The magnetic field at the centre will be (μ0\mu_0 = permeability of free space)

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Answer: (b)

  1. Arc of angle θ\theta: B=μ0Iθ4πRB = \frac{\mu_0 I\theta}{4\pi R}.
  2. θ=π2\theta = \frac{\pi}{2}: B=μ0I4πR⋅π2=μ0I8RB = \frac{\mu_0 I}{4\pi R}\cdot\frac{\pi}{2} = \frac{\mu_0 I}{8R}
  3. So the answer is (b).
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