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JEE Main 2026 (28 Jan, Shift 1) · Nucleus: Composition, Size & Nuclear Force

Nucleus: Composition, Size & Nuclear Force question from JEE Main 2026 (28 Jan, Shift 1)

Q5JEE Main 2026 · 28 JAN · SHIFT 1Medium

Nucleus: Composition, Size & Nuclear Force

An atom ${}_{3}^{8}X$ is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by:

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Answer: (c)

Electrons do not enter the nucleus; nucleons added $= 10 + 9 = 19$ .
New $A = 8 + 19 = 27$ .
Surface area $\propto R^2 \propto A^{2/3}$ : $\frac{S_2}{S_1} = \left(\frac{27}{8}\right)^{2/3} = \frac{9}{4}$ .
Growth $= \frac{9 - 4}{4} \times 100\% = 125\%$
So the answer is (c) $125\%$ .

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