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JEE Main 2004 (AIEEE) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2004 (AIEEE)

Q38JEE Main 2004 · AIEEEEasy

Equations of Kinematics

An automobile travelling with speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e 120 km/h, the stopping distance will be

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Answer: (d)

For the same retardation, $s \propto u^2$ .
Speed doubles, so $s' = 4 \times 20 = 80\text{ m}$ .
So the answer is (d) 80 m.

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