Student Login

Home›Chapters›Alternating Current PYQs›Power, Power Factor & Wattless Current›Question 23

MHT CET 2025 (20 Apr, Shift 2) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from MHT CET 2025 (20 Apr, Shift 2)

Q23MHT CET 2025 · 20 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

An e.m.f. $e = E_0 \cos\omega t$ is applied to a circuit containing $L, C$ and $R$ in series where $X_L = 3R$ and $X_C = R$ . The average power dissipated in the circuit is

Show answer and solution

Answer: (b)

$X_L - X_C = 3R - R = 2R$ , so $Z^2 = R^2 + 4R^2 = 5R^2$ .
$P = \frac{E_{rms}^2R}{Z^2} = \frac{E_0^2}{2} \cdot \frac{R}{5R^2}$ .
$P = \frac{E_0^2}{10R}$ .
So the answer is (b) $\frac{E_0^2}{10R}$ .

Report a mistake

More questions on Power, Power Factor & Wattless Current

In an L - R circuit, the inductive reactance is equal to √(3) times the resistance ' R '…MHT CET 2025 (19 Apr, Shift 2)
An inductor of reactance 100 Ω, a capacitor of reactance 50 Ω, and a resistor of…JEE Main 2025 (7 Apr, Shift 2)
The power factor of a CR circuit is 1/√(2), If the frequency of a.c. signal is halved…MHT CET 2025 (25 Apr, Shift 1)
When alternating current is passed through L - R series circuit, the power factor is…MHT CET 2025 (22 Apr, Shift 1)
An a.c. source is applied to a series LR circuit with XL = 3R and power factor is X₁. Now…MHT CET 2025 (19 Apr, Shift 2)
In LCR series circuit, an alternating e.m.f. 'e' and current ' i ' are given by equations…MHT CET 2024 (16 May, Shift 1)
In an AC circuit E = 200sin (50t) volt and I = 100sin (50t + π/3) mA. The power…MHT CET 2024 (3 May, Shift 1)
In an A.C. circuit, the potential difference ' V ' and current 'I' are given respectively…MHT CET 2024 (2 May, Shift 1)