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JEE Main 2024 (4 Apr, Shift 1) · Wire Combinations & Special Cases

Wire Combinations & Special Cases question from JEE Main 2024 (4 Apr, Shift 1)

Q6JEE Main 2024 · 4 APR · SHIFT 1Medium

Wire Combinations & Special Cases

An elastic spring under tension of 3 N3\text{ N} has a length aa. Its length is bb under tension 2 N2\text{ N}. For its length (3a−2b)(3a - 2b), the value of tension will be _______ N.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. a=L+3ca = L + 3c and b=L+2cb = L + 2c, so c=a−bc = a - b and L=3b−2aL = 3b - 2a
  2. For length 3a−2b3a - 2b: Tc=(3a−2b)−L=(3a−2b)−(3b−2a)=5(a−b)Tc = (3a - 2b) - L = (3a - 2b) - (3b - 2a) = 5(a - b)
  3. T=5(a−b)a−b=5 NT = \frac{5(a - b)}{a - b} = 5\text{ N}
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