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NEET 1994 (AIPMT) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from NEET 1994 (AIPMT)

Q100NEET 1994 · AIPMTEasy

Electrical Power & Heating Effect

An electric bulb is rated 60 W, 220 V. The resistance of its filament is

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Answer: (d)

$R = \frac{V^2}{P} = \frac{220^2}{60}$ .
$R = \frac{48400}{60} \approx 807\ \Omega$ .
So the answer is (d) $807\ \Omega$ .

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