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JEE Main 2025 (3 Apr, Shift 2) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from JEE Main 2025 (3 Apr, Shift 2)

Q12JEE Main 2025 · 3 APR · SHIFT 2Easy

AC Basics: Peak, RMS & Average Values

An electric bulb rated as $100\text{ W} - 220\text{ V}$ is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is:

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Answer: (b)

$I_{rms} = \frac{P}{V_{rms}} = \frac{100}{220} \approx 0.455$ A
$I_0 = \sqrt{2}\, I_{rms} = 1.414 \times 0.455 \approx 0.64$ A
So the answer is (b) 0.64 A.

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