An electric charge 10⁻³ is placed at the origin (0, 0) of X - Y co-ordinate system. Two points A and B are situated at (√(2), √(2)) and (2, 0) respectively. The potential difference between the points A and B will be (a) 4.5 volts (b) 9 volts (c) zero (d) 2 volts

Answer: (c). V = kq/r depends only on distance from the charge. rA = √(2+2) = 2, rB = 2 rA = rB ⇒ VA - VB = 0 So the answer is (c) zero.

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Electric Potential & Equipotentials

An electric charge $10^{-3}\,\mu\text{C}$ is placed at the origin $(0, 0)$ of $X - Y$ co-ordinate system. Two points $A$ and $B$ are situated at $\left(\sqrt{2}, \sqrt{2}\right)$ and $(2, 0)$ respectively. The potential difference between the points $A$ and $B$ will be

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Answer: (c)

$V = \frac{kq}{r}$ depends only on distance from the charge.
$r_A = \sqrt{2+2} = 2$ , $r_B = 2$
$r_A = r_B \Rightarrow V_A - V_B = 0$
So the answer is (c) zero.

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